11130032013 has 8 divisors (see below), whose sum is σ = 14866403808. Its totient is φ = 7406840784.

The previous prime is 11130031973. The next prime is 11130032033. The reversal of 11130032013 is 31023003111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2^k-11130032013 is a prime.

It is a super-2 number, since 2×11130032013² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11130031983 and 11130032001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11130032033) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3293170 + ... + 3296547.

It is an arithmetic number, because the mean of its divisors is an integer number (1858300476).

Almost surely, 2^11130032013 is an apocalyptic number.

It is an amenable number.

11130032013 is a deficient number, since it is larger than the sum of its proper divisors (3736371795).

11130032013 is an equidigital number, since it uses as much as digits as its factorization.

11130032013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6590283.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 11130032013 its reverse (31023003111), we get a palindrome (42153035124).

The spelling of 11130032013 in words is "eleven billion, one hundred thirty million, thirty-two thousand, thirteen".