1113004001400 has 384 divisors, whose sum is σ = 3596769792000. Its totient is φ = 284501859840.

The previous prime is 1113004001321. The next prime is 1113004001413. The reversal of 1113004001400 is 41004003111.

It is a super-2 number, since 2×1113004001400² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 1113004001400.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 510785511 + ... + 510787689.

It is an arithmetic number, because the mean of its divisors is an integer number (9366588000).

Almost surely, 2^{1113004001400} is an apocalyptic number.

1113004001400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1113004001400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1798384896000).

1113004001400 is an abundant number, since it is smaller than the sum of its proper divisors (2483765790600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1113004001400 is a wasteful number, since it uses less digits than its factorization.

1113004001400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2611 (or 2602 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 1113004001400 its reverse (41004003111), we get a palindrome (1154008004511).

The spelling of 1113004001400 in words is "one trillion, one hundred thirteen billion, four million, one thousand, four hundred".