11130043332 has 12 divisors (see below), whose sum is σ = 25970101136. Its totient is φ = 3710014440.

The previous prime is 11130043289. The next prime is 11130043333. The reversal of 11130043332 is 23334003111.

It is a tau number, because it is divible by the number of its divisors (12).

It is a junction number, because it is equal to n+sod(n) for n = 11130043299 and 11130043308.

It is not an unprimeable number, because it can be changed into a prime (11130043333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 463751794 + ... + 463751817.

Almost surely, 2^11130043332 is an apocalyptic number.

11130043332 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

11130043332 is an abundant number, since it is smaller than the sum of its proper divisors (14840057804).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11130043332 is a wasteful number, since it uses less digits than its factorization.

11130043332 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 927503618 (or 927503616 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 11130043332 its reverse (23334003111), we get a palindrome (34464046443).

The spelling of 11130043332 in words is "eleven billion, one hundred thirty million, forty-three thousand, three hundred thirty-two".