Base | Representation |
---|---|
bin | 10000001100100100100… |
… | …100010100101000010011 |
3 | 10221101212120201211022022 |
4 | 100030210210110220103 |
5 | 121213421031443443 |
6 | 2211150523402055 |
7 | 143261266111304 |
oct | 20144444245023 |
9 | 3841776654268 |
10 | 1113010031123 |
11 | 39a030167a31 |
12 | 15b86098332b |
13 | 80c5827ca43 |
14 | 3bc272c47ab |
15 | 1de42c34e68 |
hex | 10324914a13 |
1113010031123 has 2 divisors, whose sum is σ = 1113010031124. Its totient is φ = 1113010031122.
The previous prime is 1113010031101. The next prime is 1113010031131. The reversal of 1113010031123 is 3211300103111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1113010031123 is a prime.
It is a super-2 number, since 2×11130100311232 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (1113010031153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556505015561 + 556505015562.
It is an arithmetic number, because the mean of its divisors is an integer number (556505015562).
Almost surely, 21113010031123 is an apocalyptic number.
1113010031123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113010031123 is an equidigital number, since it uses as much as digits as its factorization.
1113010031123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 1113010031123 its reverse (3211300103111), we get a palindrome (4324310134234).
The spelling of 1113010031123 in words is "one trillion, one hundred thirteen billion, ten million, thirty-one thousand, one hundred twenty-three".
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