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1113021231300 = 22325211372412003
BaseRepresentation
bin10000001100100101001…
…111000011000011000100
310221101220100210212001200
4100030211033003003010
5121213431413400200
62211152003422500
7143261463240006
oct20144517030304
93841810725050
101113021231300
1139a036517880
1215b864684a30
1380c5a6a1974
143bc2899c376
151de43be8800
hex103253c30c4

1113021231300 has 648 divisors, whose sum is σ = 4008901976352. Its totient is φ = 255999744000.

The previous prime is 1113021231293. The next prime is 1113021231319. The reversal of 1113021231300 is 31321203111.

1113021231300 is a `hidden beast` number, since 1 + 1 + 130 + 2 + 1 + 231 + 300 = 666.

It is a super-2 number, since 2×11130212313002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 215 ways as a sum of consecutive naturals, for example, 555676099 + ... + 555678101.

It is an arithmetic number, because the mean of its divisors is an integer number (6186577124).

Almost surely, 21113021231300 is an apocalyptic number.

1113021231300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1113021231300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2004450988176).

1113021231300 is an abundant number, since it is smaller than the sum of its proper divisors (2895880745052).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1113021231300 is a wasteful number, since it uses less digits than its factorization.

1113021231300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2149 (or 2102 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 1113021231300 its reverse (31321203111), we get a palindrome (1144342434411).

The spelling of 1113021231300 in words is "one trillion, one hundred thirteen billion, twenty-one million, two hundred thirty-one thousand, three hundred".