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1113033113130 = 23537101103771
BaseRepresentation
bin10000001100100101111…
…100010111111000101010
310221101221012011111212110
4100030211330113320222
5121213442434110010
62211153110223150
7143261666234631
oct20144574277052
93841835144773
101113033113130
1139a0421a2874
1215b868654ab6
1380c5cca1c33
143bc2a3b2518
151de44c94120
hex10325f17e2a

1113033113130 has 16 divisors (see below), whose sum is σ = 2671279471584. Its totient is φ = 296808830160.

The previous prime is 1113033113119. The next prime is 1113033113149. The reversal of 1113033113130 is 313113303111.

It is a junction number, because it is equal to n+sod(n) for n = 1113033113097 and 1113033113106.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18550551856 + ... + 18550551915.

It is an arithmetic number, because the mean of its divisors is an integer number (166954966974).

Almost surely, 21113033113130 is an apocalyptic number.

1113033113130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1113033113130 is an abundant number, since it is smaller than the sum of its proper divisors (1558246358454).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1113033113130 is a wasteful number, since it uses less digits than its factorization.

1113033113130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37101103781.

The product of its (nonzero) digits is 243, while the sum is 21.

Adding to 1113033113130 its reverse (313113303111), we get a palindrome (1426146416241).

The spelling of 1113033113130 in words is "one trillion, one hundred thirteen billion, thirty-three million, one hundred thirteen thousand, one hundred thirty".

Divisors: 1 2 3 5 6 10 15 30 37101103771 74202207542 111303311313 185505518855 222606622626 371011037710 556516556565 1113033113130