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1113043307 is a prime number
BaseRepresentation
bin100001001010111…
…1011000101101011
32212120101110101012
41002111323011223
54234414341212
6302240214135
736403466135
oct10225730553
92776343335
101113043307
11521313a02
1227090a34b
1314979980c
14a7b76055
1567ab0922
hex4257b16b

1113043307 has 2 divisors, whose sum is σ = 1113043308. Its totient is φ = 1113043306.

The previous prime is 1113043303. The next prime is 1113043369. The reversal of 1113043307 is 7033403111.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1113043307 - 22 = 1113043303 is a prime.

It is not a weakly prime, because it can be changed into another prime (1113043303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556521653 + 556521654.

It is an arithmetic number, because the mean of its divisors is an integer number (556521654).

Almost surely, 21113043307 is an apocalyptic number.

1113043307 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113043307 is an equidigital number, since it uses as much as digits as its factorization.

1113043307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 756, while the sum is 23.

The square root of 1113043307 is about 33362.3036824497. The cubic root of 1113043307 is about 1036.3441991600.

Adding to 1113043307 its reverse (7033403111), we get a palindrome (8146446418).

The spelling of 1113043307 in words is "one billion, one hundred thirteen million, forty-three thousand, three hundred seven".