Base | Representation |
---|---|
bin | 10000001100101001100… |
… | …011111110111110001011 |
3 | 10221102002102102011200112 |
4 | 100030221203332332023 |
5 | 121214104010002431 |
6 | 2211203115424535 |
7 | 143263334301431 |
oct | 20145143767613 |
9 | 3842072364615 |
10 | 1113093828491 |
11 | 39a0734a2157 |
12 | 15b884a5514b |
13 | 80c6c73c698 |
14 | 3bc34498d51 |
15 | 1de4a288c2b |
hex | 103298fef8b |
1113093828491 has 2 divisors, whose sum is σ = 1113093828492. Its totient is φ = 1113093828490.
The previous prime is 1113093828479. The next prime is 1113093828493. The reversal of 1113093828491 is 1948283903111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1113093828491 - 214 = 1113093812107 is a prime.
Together with 1113093828493, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1113093828493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556546914245 + 556546914246.
It is an arithmetic number, because the mean of its divisors is an integer number (556546914246).
Almost surely, 21113093828491 is an apocalyptic number.
1113093828491 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113093828491 is an equidigital number, since it uses as much as digits as its factorization.
1113093828491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 373248, while the sum is 50.
The spelling of 1113093828491 in words is "one trillion, one hundred thirteen billion, ninety-three million, eight hundred twenty-eight thousand, four hundred ninety-one".
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