11131012123333 has 4 divisors (see below), whose sum is σ = 11180926976128. Its totient is φ = 11081097270540.

The previous prime is 11131012123313. The next prime is 11131012123339. The reversal of 11131012123333 is 33332121013111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11131012123333 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11131012123298 and 11131012123307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11131012123339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24957426063 + ... + 24957426508.

It is an arithmetic number, because the mean of its divisors is an integer number (2795231744032).

Almost surely, 2^{11131012123333} is an apocalyptic number.

It is an amenable number.

11131012123333 is a deficient number, since it is larger than the sum of its proper divisors (49914852795).

11131012123333 is an equidigital number, since it uses as much as digits as its factorization.

11131012123333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49914852794.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 11131012123333 its reverse (33332121013111), we get a palindrome (44463133136444).

The spelling of 11131012123333 in words is "eleven trillion, one hundred thirty-one billion, twelve million, one hundred twenty-three thousand, three hundred thirty-three".