Base | Representation |
---|---|
bin | 110011110101010011… |
… | …0011100111110110010 |
3 | 101122022101122112101222 |
4 | 1213222212130332302 |
5 | 3310430343143442 |
6 | 123045110225042 |
7 | 11020240334501 |
oct | 1475246347662 |
9 | 348271575358 |
10 | 111310131122 |
11 | 4322a738003 |
12 | 196a5655182 |
13 | a65ba71318 |
14 | 555d1c0838 |
15 | 2d671398d2 |
hex | 19ea99cfb2 |
111310131122 has 4 divisors (see below), whose sum is σ = 166965196686. Its totient is φ = 55655065560.
The previous prime is 111310131113. The next prime is 111310131131. The reversal of 111310131122 is 221131013111.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 221131013111 = 241 ⋅917556071.
It is an interprime number because it is at equal distance from previous prime (111310131113) and next prime (111310131131).
It can be written as a sum of positive squares in only one way, i.e., 64277967961 + 47032163161 = 253531^2 + 216869^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 111310131122.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27827532779 + ... + 27827532782.
Almost surely, 2111310131122 is an apocalyptic number.
111310131122 is a deficient number, since it is larger than the sum of its proper divisors (55655065564).
111310131122 is an equidigital number, since it uses as much as digits as its factorization.
111310131122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55655065563.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 111310131122 its reverse (221131013111), we get a palindrome (332441144233).
The spelling of 111310131122 in words is "one hundred eleven billion, three hundred ten million, one hundred thirty-one thousand, one hundred twenty-two".
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