11131013414003 has 4 divisors (see below), whose sum is σ = 12721158187440. Its totient is φ = 9540868640568.

The previous prime is 11131013413999. The next prime is 11131013414051. The reversal of 11131013414003 is 30041431013111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11131013414003 - 2² = 11131013413999 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11131013414003.

It is not an unprimeable number, because it can be changed into a prime (11131013414063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 795072386708 + ... + 795072386721.

It is an arithmetic number, because the mean of its divisors is an integer number (3180289546860).

Almost surely, 2^{11131013414003} is an apocalyptic number.

11131013414003 is a deficient number, since it is larger than the sum of its proper divisors (1590144773437).

11131013414003 is an equidigital number, since it uses as much as digits as its factorization.

11131013414003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1590144773436.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 11131013414003 its reverse (30041431013111), we get a palindrome (41172444427114).

The spelling of 11131013414003 in words is "eleven trillion, one hundred thirty-one billion, thirteen million, four hundred fourteen thousand, three".