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11131041041 is a prime number
BaseRepresentation
bin10100101110111011…
…00011010100010001
31001201202000110202022
422113131203110101
5140244021303131
65040304501225
7542560200461
oct122735432421
931652013668
1011131041041
1147a220097a
1221a791a815
131085118c23
14778461ba1
1545232637b
hex297763511

11131041041 has 2 divisors, whose sum is σ = 11131041042. Its totient is φ = 11131041040.

The previous prime is 11131041013. The next prime is 11131041059. The reversal of 11131041041 is 14014013111.

11131041041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6441667600 + 4689373441 = 80260^2 + 68479^2 .

It is a cyclic number.

It is not a de Polignac number, because 11131041041 - 222 = 11126846737 is a prime.

It is not a weakly prime, because it can be changed into another prime (11131041001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565520520 + 5565520521.

It is an arithmetic number, because the mean of its divisors is an integer number (5565520521).

Almost surely, 211131041041 is an apocalyptic number.

It is an amenable number.

11131041041 is a deficient number, since it is larger than the sum of its proper divisors (1).

11131041041 is an equidigital number, since it uses as much as digits as its factorization.

11131041041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 11131041041 its reverse (14014013111), we get a palindrome (25145054152).

The spelling of 11131041041 in words is "eleven billion, one hundred thirty-one million, forty-one thousand, forty-one".