Base | Representation |
---|---|
bin | 10100101110111011… |
… | …00110000111110011 |
3 | 1001201202001001111212 |
4 | 22113131212013303 |
5 | 140244022140111 |
6 | 5040305030335 |
7 | 542560246124 |
oct | 122735460763 |
9 | 31652031455 |
10 | 11131052531 |
11 | 47a2209575 |
12 | 21a79253ab |
13 | 1085121221 |
14 | 77846604b |
15 | 45232998b |
hex | 2977661f3 |
11131052531 has 4 divisors (see below), whose sum is σ = 11313528864. Its totient is φ = 10948576200.
The previous prime is 11131052507. The next prime is 11131052539. The reversal of 11131052531 is 13525013111.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13525013111 = 2239 ⋅6040649.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11131052531 is a prime.
It is a super-2 number, since 2×111310525312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11131052497 and 11131052506.
It is not an unprimeable number, because it can be changed into a prime (11131052539) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91238075 + ... + 91238196.
It is an arithmetic number, because the mean of its divisors is an integer number (2828382216).
Almost surely, 211131052531 is an apocalyptic number.
11131052531 is a deficient number, since it is larger than the sum of its proper divisors (182476333).
11131052531 is an equidigital number, since it uses as much as digits as its factorization.
11131052531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 182476332.
The product of its (nonzero) digits is 450, while the sum is 23.
Adding to 11131052531 its reverse (13525013111), we get a palindrome (24656065642).
The spelling of 11131052531 in words is "eleven billion, one hundred thirty-one million, fifty-two thousand, five hundred thirty-one".
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