1113110021011 has 2 divisors, whose sum is σ = 1113110021012. Its totient is φ = 1113110021010.

The previous prime is 1113110020999. The next prime is 1113110021081. The reversal of 1113110021011 is 1101200113111.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1113110021011 is a prime.

It is a super-2 number, since 2×1113110021011² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1113110020982 and 1113110021000.

It is not a weakly prime, because it can be changed into another prime (1113110021081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556555010505 + 556555010506.

It is an arithmetic number, because the mean of its divisors is an integer number (556555010506).

Almost surely, 2^{1113110021011} is an apocalyptic number.

1113110021011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113110021011 is an equidigital number, since it uses as much as digits as its factorization.

1113110021011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 1113110021011 its reverse (1101200113111), we get a palindrome (2214310134122).

The spelling of 1113110021011 in words is "one trillion, one hundred thirteen billion, one hundred ten million, twenty-one thousand, eleven".