Base | Representation |
---|---|
bin | 10100101110111011… |
… | …10010110010010001 |
3 | 1001201202010200122222 |
4 | 22113131302302101 |
5 | 140244030320101 |
6 | 5040310110425 |
7 | 542560553264 |
oct | 122735626221 |
9 | 31652120588 |
10 | 11131104401 |
11 | 47a224453a |
12 | 21a794b415 |
13 | 108513ba11 |
14 | 77847acdb |
15 | 45233a01b |
hex | 297772c91 |
11131104401 has 4 divisors (see below), whose sum is σ = 11140676592. Its totient is φ = 11121532212.
The previous prime is 11131104379. The next prime is 11131104407. The reversal of 11131104401 is 10440113111.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11131104401 - 26 = 11131104337 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 11131104401.
It is not an unprimeable number, because it can be changed into a prime (11131104407) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4784351 + ... + 4786676.
It is an arithmetic number, because the mean of its divisors is an integer number (2785169148).
Almost surely, 211131104401 is an apocalyptic number.
It is an amenable number.
11131104401 is a deficient number, since it is larger than the sum of its proper divisors (9572191).
11131104401 is an equidigital number, since it uses as much as digits as its factorization.
11131104401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9572190.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 11131104401 its reverse (10440113111), we get a palindrome (21571217512).
The spelling of 11131104401 in words is "eleven billion, one hundred thirty-one million, one hundred four thousand, four hundred one".
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