11131113113 has 4 divisors (see below), whose sum is σ = 11141205888. Its totient is φ = 11121020340.

The previous prime is 11131113109. The next prime is 11131113127. The reversal of 11131113113 is 31131113111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11131113113 - 2² = 11131113109 is a prime.

It is a super-3 number, since 3×11131113113³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11131113091 and 11131113100.

It is not an unprimeable number, because it can be changed into a prime (11131113163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5044733 + ... + 5046938.

It is an arithmetic number, because the mean of its divisors is an integer number (2785301472).

Almost surely, 2^11131113113 is an apocalyptic number.

It is an amenable number.

11131113113 is a deficient number, since it is larger than the sum of its proper divisors (10092775).

11131113113 is a wasteful number, since it uses less digits than its factorization.

11131113113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10092774.

The product of its digits is 27, while the sum is 17.

Adding to 11131113113 its reverse (31131113111), we get a palindrome (42262226224).

The spelling of 11131113113 in words is "eleven billion, one hundred thirty-one million, one hundred thirteen thousand, one hundred thirteen".