Base | Representation |
---|---|
bin | 11001010011110010100100… |
… | …100000000100001010100011 |
3 | 112121010020111012022021211111 |
4 | 121103302210200010022203 |
5 | 104042210144332442402 |
6 | 1032423343411324151 |
7 | 32305651424345101 |
oct | 3123624440041243 |
9 | 477106435267744 |
10 | 111311132312227 |
11 | 32515871351321 |
12 | 10598a14bb0657 |
13 | 4a1579683b2a3 |
14 | 1d6b6b7b9cc71 |
15 | cd06d0b109d7 |
hex | 653ca48042a3 |
111311132312227 has 2 divisors, whose sum is σ = 111311132312228. Its totient is φ = 111311132312226.
The previous prime is 111311132312197. The next prime is 111311132312269. The reversal of 111311132312227 is 722213231113111.
It is a weak prime.
It is an emirp because it is prime and its reverse (722213231113111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 111311132312227 - 223 = 111311123923619 is a prime.
It is not a weakly prime, because it can be changed into another prime (111311132312287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55655566156113 + 55655566156114.
It is an arithmetic number, because the mean of its divisors is an integer number (55655566156114).
Almost surely, 2111311132312227 is an apocalyptic number.
111311132312227 is a deficient number, since it is larger than the sum of its proper divisors (1).
111311132312227 is an equidigital number, since it uses as much as digits as its factorization.
111311132312227 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3024, while the sum is 31.
Adding to 111311132312227 its reverse (722213231113111), we get a palindrome (833524363425338).
The spelling of 111311132312227 in words is "one hundred eleven trillion, three hundred eleven billion, one hundred thirty-two million, three hundred twelve thousand, two hundred twenty-seven".
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