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111311132312197 is a prime number
BaseRepresentation
bin11001010011110010100100…
…100000000100001010000101
3112121010020111012022021210101
4121103302210200010022011
5104042210144332442242
61032423343411324101
732305651424345026
oct3123624440041205
9477106435267711
10111311132312197
11325158713512a4
1210598a14bb0631
134a1579683b27c
141d6b6b7b9cc4d
15cd06d0b109b7
hex653ca4804285

111311132312197 has 2 divisors, whose sum is σ = 111311132312198. Its totient is φ = 111311132312196.

The previous prime is 111311132312173. The next prime is 111311132312227. The reversal of 111311132312197 is 791213231113111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106744252187521 + 4566880124676 = 10331711^2 + 2137026^2 .

It is an emirp because it is prime and its reverse (791213231113111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111311132312197 - 215 = 111311132279429 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111311132312297) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55655566156098 + 55655566156099.

It is an arithmetic number, because the mean of its divisors is an integer number (55655566156099).

Almost surely, 2111311132312197 is an apocalyptic number.

It is an amenable number.

111311132312197 is a deficient number, since it is larger than the sum of its proper divisors (1).

111311132312197 is an equidigital number, since it uses as much as digits as its factorization.

111311132312197 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6804, while the sum is 37.

The spelling of 111311132312197 in words is "one hundred eleven trillion, three hundred eleven billion, one hundred thirty-two million, three hundred twelve thousand, one hundred ninety-seven".