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11131120022040 = 2335519710515531
BaseRepresentation
bin1010000111111010101001…
…1101000111001000011000
31110102010100220002221100000
42201332222131013020120
52424333013211201130
635401322124413000
72226124350034134
oct241765235071030
943363326087300
1011131120022040
113601755079197
1212b93516a7160
13629877369a05
142a6a6b6b23c4
1514482ca0b260
hexa1faa747218

11131120022040 has 384 divisors, whose sum is σ = 37749134142720. Its totient is φ = 2949887808000.

The previous prime is 11131120022021. The next prime is 11131120022041. The reversal of 11131120022040 is 4022002113111.

11131120022040 is a `hidden beast` number, since 111 + 311 + 20 + 0 + 220 + 4 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11131120022041) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 2012494075 + ... + 2012499605.

It is an arithmetic number, because the mean of its divisors is an integer number (98305036830).

Almost surely, 211131120022040 is an apocalyptic number.

11131120022040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11131120022040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18874567071360).

11131120022040 is an abundant number, since it is smaller than the sum of its proper divisors (26618014120680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11131120022040 is a wasteful number, since it uses less digits than its factorization.

11131120022040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6805 (or 6789 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 11131120022040 its reverse (4022002113111), we get a palindrome (15153122135151).

The spelling of 11131120022040 in words is "eleven trillion, one hundred thirty-one billion, one hundred twenty million, twenty-two thousand, forty".