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11131120153 is a prime number
BaseRepresentation
bin10100101110111011…
…10110101000011001
31001201202011111021101
422113131312220121
5140244031321103
65040310311401
7542560650226
oct122735665031
931652144241
1011131120153
1147a225535a
1221a7958561
131085145c3a
1477848294d
1545233ea1d
hex297776a19

11131120153 has 2 divisors, whose sum is σ = 11131120154. Its totient is φ = 11131120152.

The previous prime is 11131120111. The next prime is 11131120157. The reversal of 11131120153 is 35102113111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10153182169 + 977937984 = 100763^2 + 31272^2 .

It is a cyclic number.

It is not a de Polignac number, because 11131120153 - 29 = 11131119641 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11131120153.

It is not a weakly prime, because it can be changed into another prime (11131120157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565560076 + 5565560077.

It is an arithmetic number, because the mean of its divisors is an integer number (5565560077).

Almost surely, 211131120153 is an apocalyptic number.

It is an amenable number.

11131120153 is a deficient number, since it is larger than the sum of its proper divisors (1).

11131120153 is an equidigital number, since it uses as much as digits as its factorization.

11131120153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 19.

Adding to 11131120153 its reverse (35102113111), we get a palindrome (46233233264).

The spelling of 11131120153 in words is "eleven billion, one hundred thirty-one million, one hundred twenty thousand, one hundred fifty-three".