Base | Representation |
---|---|
bin | 10100101110111011… |
… | …11001000010110001 |
3 | 1001201202011222211022 |
4 | 22113131321002301 |
5 | 140244032130113 |
6 | 5040310425225 |
7 | 542561021102 |
oct | 122735710261 |
9 | 31652158738 |
10 | 11131130033 |
11 | 47a2261821 |
12 | 21a7962215 |
13 | 108514a59a |
14 | 7784863a9 |
15 | 452342908 |
hex | 2977790b1 |
11131130033 has 2 divisors, whose sum is σ = 11131130034. Its totient is φ = 11131130032.
The previous prime is 11131129981. The next prime is 11131130047. The reversal of 11131130033 is 33003113111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10127000689 + 1004129344 = 100633^2 + 31688^2 .
It is a cyclic number.
It is not a de Polignac number, because 11131130033 - 218 = 11130867889 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11131129993 and 11131130020.
It is not a weakly prime, because it can be changed into another prime (11131130063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565565016 + 5565565017.
It is an arithmetic number, because the mean of its divisors is an integer number (5565565017).
Almost surely, 211131130033 is an apocalyptic number.
It is an amenable number.
11131130033 is a deficient number, since it is larger than the sum of its proper divisors (1).
11131130033 is an equidigital number, since it uses as much as digits as its factorization.
11131130033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 11131130033 its reverse (33003113111), we get a palindrome (44134243144).
The spelling of 11131130033 in words is "eleven billion, one hundred thirty-one million, one hundred thirty thousand, thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •