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111312284437 is a prime number
BaseRepresentation
bin110011110101010111…
…0101010101100010101
3101122022112200221012101
41213222232222230111
53310431421100222
6123045224322101
711020264543414
oct1475256525425
9348275627171
10111312284437
1143230978902
12196a6313331
13a65c346483
14555d5c147b
152d67412927
hex19eabaab15

111312284437 has 2 divisors, whose sum is σ = 111312284438. Its totient is φ = 111312284436.

The previous prime is 111312284423. The next prime is 111312284449. The reversal of 111312284437 is 734482213111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107191414801 + 4120869636 = 327401^2 + 64194^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111312284437 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111312284396 and 111312284405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111312284407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55656142218 + 55656142219.

It is an arithmetic number, because the mean of its divisors is an integer number (55656142219).

Almost surely, 2111312284437 is an apocalyptic number.

It is an amenable number.

111312284437 is a deficient number, since it is larger than the sum of its proper divisors (1).

111312284437 is an equidigital number, since it uses as much as digits as its factorization.

111312284437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 32256, while the sum is 37.

Adding to 111312284437 its reverse (734482213111), we get a palindrome (845794497548).

The spelling of 111312284437 in words is "one hundred eleven billion, three hundred twelve million, two hundred eighty-four thousand, four hundred thirty-seven".