Base | Representation |
---|---|
bin | 10000001100101011110… |
… | …010100101110101000111 |
3 | 10221102012000202110100202 |
4 | 100030223302211311013 |
5 | 121214143042241403 |
6 | 2211210533001115 |
7 | 143264300121521 |
oct | 20145362456507 |
9 | 3842160673322 |
10 | 1113131212103 |
11 | 39a092605aa9 |
12 | 15b89548319b |
13 | 80c773cb371 |
14 | 3bc3942aa11 |
15 | 1de4d6c0688 |
hex | 1032bca5d47 |
1113131212103 has 2 divisors, whose sum is σ = 1113131212104. Its totient is φ = 1113131212102.
The previous prime is 1113131212097. The next prime is 1113131212121. The reversal of 1113131212103 is 3012121313111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1113131212103 - 28 = 1113131211847 is a prime.
It is a super-2 number, since 2×11131312121032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113131212133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556565606051 + 556565606052.
It is an arithmetic number, because the mean of its divisors is an integer number (556565606052).
Almost surely, 21113131212103 is an apocalyptic number.
1113131212103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113131212103 is an equidigital number, since it uses as much as digits as its factorization.
1113131212103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 1113131212103 its reverse (3012121313111), we get a palindrome (4125252525214).
The spelling of 1113131212103 in words is "one trillion, one hundred thirteen billion, one hundred thirty-one million, two hundred twelve thousand, one hundred three".
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