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111313132310951 is a prime number
BaseRepresentation
bin11001010011110100011011…
…101101011101000110100111
3112121010102122120122202022022
4121103310123231131012213
5104042223243332422301
61032424314054253355
732306052121143134
oct3123643355350647
9477112576582268
10111313132310951
11325166a8297a2a
121059929295725b
134a15a24cb4b9c
141d6b82765758b
15cd079b4c2d1b
hex653d1bb5d1a7

111313132310951 has 2 divisors, whose sum is σ = 111313132310952. Its totient is φ = 111313132310950.

The previous prime is 111313132310827. The next prime is 111313132311019. The reversal of 111313132310951 is 159013231313111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 111313132310951 - 210 = 111313132309927 is a prime.

It is a super-2 number, since 2×1113131323109512 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111313132313951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55656566155475 + 55656566155476.

It is an arithmetic number, because the mean of its divisors is an integer number (55656566155476).

Almost surely, 2111313132310951 is an apocalyptic number.

111313132310951 is a deficient number, since it is larger than the sum of its proper divisors (1).

111313132310951 is an equidigital number, since it uses as much as digits as its factorization.

111313132310951 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7290, while the sum is 35.

The spelling of 111313132310951 in words is "one hundred eleven trillion, three hundred thirteen billion, one hundred thirty-two million, three hundred ten thousand, nine hundred fifty-one".