11131320110033 has 4 divisors (see below), whose sum is σ = 11142116735808. Its totient is φ = 11120523484260.

The previous prime is 11131320110017. The next prime is 11131320110039. The reversal of 11131320110033 is 33001102313111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11131320110033 - 2⁴ = 11131320110017 is a prime.

It is a super-2 number, since 2×11131320110033² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11131320109987 and 11131320110014.

It is not an unprimeable number, because it can be changed into a prime (11131320110039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5398311341 + ... + 5398313402.

It is an arithmetic number, because the mean of its divisors is an integer number (2785529183952).

Almost surely, 2^{11131320110033} is an apocalyptic number.

It is an amenable number.

11131320110033 is a deficient number, since it is larger than the sum of its proper divisors (10796625775).

11131320110033 is a wasteful number, since it uses less digits than its factorization.

11131320110033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10796625774.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 11131320110033 its reverse (33001102313111), we get a palindrome (44132422423144).

The spelling of 11131320110033 in words is "eleven trillion, one hundred thirty-one billion, three hundred twenty million, one hundred ten thousand, thirty-three".