111313331400013 has 4 divisors (see below), whose sum is σ = 112163051487168. Its totient is φ = 110463611312860.

The previous prime is 111313331399971. The next prime is 111313331400031. The reversal of 111313331400013 is 310004133313111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111313331400013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111313331400043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 424860043381 + ... + 424860043642.

It is an arithmetic number, because the mean of its divisors is an integer number (28040762871792).

Almost surely, 2^{111313331400013} is an apocalyptic number.

It is an amenable number.

111313331400013 is a deficient number, since it is larger than the sum of its proper divisors (849720087155).

111313331400013 is an equidigital number, since it uses as much as digits as its factorization.

111313331400013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 849720087154.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 111313331400013 its reverse (310004133313111), we get a palindrome (421317464713124).

The spelling of 111313331400013 in words is "one hundred eleven trillion, three hundred thirteen billion, three hundred thirty-one million, four hundred thousand, thirteen".