1113143411131 has 4 divisors (see below), whose sum is σ = 1115919330264. Its totient is φ = 1110367492000.

The previous prime is 1113143411129. The next prime is 1113143411147. The reversal of 1113143411131 is 1311143413111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1113143411131 - 2¹ = 1113143411129 is a prime.

It is a super-2 number, since 2×1113143411131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1113143411096 and 1113143411105.

It is not an unprimeable number, because it can be changed into a prime (1113149411131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1387958965 + ... + 1387959766.

It is an arithmetic number, because the mean of its divisors is an integer number (278979832566).

Almost surely, 2^{1113143411131} is an apocalyptic number.

1113143411131 is a deficient number, since it is larger than the sum of its proper divisors (2775919133).

1113143411131 is an equidigital number, since it uses as much as digits as its factorization.

1113143411131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2775919132.

The product of its digits is 432, while the sum is 25.

Adding to 1113143411131 its reverse (1311143413111), we get a palindrome (2424286824242).

The spelling of 1113143411131 in words is "one trillion, one hundred thirteen billion, one hundred forty-three million, four hundred eleven thousand, one hundred thirty-one".