Base | Representation |
---|---|
bin | 1010000111111011111000… |
… | …1000111000110111111011 |
3 | 1110102011012220112000121211 |
4 | 2201332332020320313323 |
5 | 2424334202231440313 |
6 | 35401415002543551 |
7 | 2226135500043631 |
oct | 241767610706773 |
9 | 43364186460554 |
10 | 11131450265083 |
11 | 3601904529725 |
12 | 12b9424207bb7 |
13 | 6298ca8c62b5 |
14 | 2a6a9d4b9351 |
15 | 14484b9e0e3d |
hex | a1fbe238dfb |
11131450265083 has 2 divisors, whose sum is σ = 11131450265084. Its totient is φ = 11131450265082.
The previous prime is 11131450265077. The next prime is 11131450265231. The reversal of 11131450265083 is 38056205413111.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11131450265083 is a prime.
It is not a weakly prime, because it can be changed into another prime (11131450265053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565725132541 + 5565725132542.
It is an arithmetic number, because the mean of its divisors is an integer number (5565725132542).
Almost surely, 211131450265083 is an apocalyptic number.
11131450265083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11131450265083 is an equidigital number, since it uses as much as digits as its factorization.
11131450265083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 40.
Adding to 11131450265083 its reverse (38056205413111), we get a palindrome (49187655678194).
The spelling of 11131450265083 in words is "eleven trillion, one hundred thirty-one billion, four hundred fifty million, two hundred sixty-five thousand, eighty-three".
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