Search a number
-
+
11132004044003 = 53210037812151
BaseRepresentation
bin1010000111111101111100…
…1001011000110011100011
31110102012122111112220111012
42201333133021120303203
52424341321013402003
635401545544211135
72226155303064503
oct241773711306343
943365574486435
1011132004044003
113602069087a57
1212b9559769aab
1362998855a82b
142a6b12c6da03
1514488042d8d8
hexa1fdf258ce3

11132004044003 has 4 divisors (see below), whose sum is σ = 11342041856208. Its totient is φ = 10921966231800.

The previous prime is 11132004043999. The next prime is 11132004044023. The reversal of 11132004044003 is 30044040023111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11132004044003 - 22 = 11132004043999 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11132004044003.

It is not an unprimeable number, because it can be changed into a prime (11132004044023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105018906023 + ... + 105018906128.

It is an arithmetic number, because the mean of its divisors is an integer number (2835510464052).

Almost surely, 211132004044003 is an apocalyptic number.

11132004044003 is a deficient number, since it is larger than the sum of its proper divisors (210037812205).

11132004044003 is an equidigital number, since it uses as much as digits as its factorization.

11132004044003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 210037812204.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 11132004044003 its reverse (30044040023111), we get a palindrome (41176044067114).

The spelling of 11132004044003 in words is "eleven trillion, one hundred thirty-two billion, four million, forty-four thousand, three".

Divisors: 1 53 210037812151 11132004044003