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11132022301333 = 29383862837977
BaseRepresentation
bin1010000111111110000000…
…1111000010001010010101
31110102012200202220110211121
42201333200033002022111
52424341340202120313
635401551435403541
72226155614215043
oct241774017021225
943365622813747
1011132022301333
113602078417a5a
1212b95638b35b1
1362998c28099b
142a6b15463393
15144881d3828d
hexa1fe03c2295

11132022301333 has 4 divisors (see below), whose sum is σ = 11515885139340. Its totient is φ = 10748159463328.

The previous prime is 11132022301331. The next prime is 11132022301357. The reversal of 11132022301333 is 33310322023111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2895248580849 + 8236773720484 = 1701543^2 + 2869978^2 .

It is a cyclic number.

It is not a de Polignac number, because 11132022301333 - 21 = 11132022301331 is a prime.

It is a super-2 number, since 2×111320223013332 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11132022301298 and 11132022301307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11132022301331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 191931418960 + ... + 191931419017.

It is an arithmetic number, because the mean of its divisors is an integer number (2878971284835).

Almost surely, 211132022301333 is an apocalyptic number.

It is an amenable number.

11132022301333 is a deficient number, since it is larger than the sum of its proper divisors (383862838007).

11132022301333 is an equidigital number, since it uses as much as digits as its factorization.

11132022301333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 383862838006.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 11132022301333 its reverse (33310322023111), we get a palindrome (44442344324444).

The spelling of 11132022301333 in words is "eleven trillion, one hundred thirty-two billion, twenty-two million, three hundred one thousand, three hundred thirty-three".

Divisors: 1 29 383862837977 11132022301333