Base | Representation |
---|---|
bin | 1010000111111110000011… |
… | …0101100110110110111111 |
3 | 1110102012201110221012121012 |
4 | 2201333200311212312333 |
5 | 2424341400244204434 |
6 | 35401552440225435 |
7 | 2226156066161342 |
oct | 241774065466677 |
9 | 43365643835535 |
10 | 11132032413119 |
11 | 36020830a4102 |
12 | 12b956716b27b |
13 | 6299913b13a7 |
14 | 2a6b16936459 |
15 | 144882b843ce |
hex | a1fe0d66dbf |
11132032413119 has 2 divisors, whose sum is σ = 11132032413120. Its totient is φ = 11132032413118.
The previous prime is 11132032413109. The next prime is 11132032413133. The reversal of 11132032413119 is 91131423023111.
It is a weak prime.
It is an emirp because it is prime and its reverse (91131423023111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11132032413119 - 28 = 11132032412863 is a prime.
It is a super-2 number, since 2×111320324131192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11132032413109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566016206559 + 5566016206560.
It is an arithmetic number, because the mean of its divisors is an integer number (5566016206560).
Almost surely, 211132032413119 is an apocalyptic number.
11132032413119 is a deficient number, since it is larger than the sum of its proper divisors (1).
11132032413119 is an equidigital number, since it uses as much as digits as its factorization.
11132032413119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 32.
The spelling of 11132032413119 in words is "eleven trillion, one hundred thirty-two billion, thirty-two million, four hundred thirteen thousand, one hundred nineteen".
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