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11132100104231 is a prime number
BaseRepresentation
bin1010000111111110010011…
…0111110101000000100111
31110102012220012022021100102
42201333210313311000213
52424342020111313411
635402003255134315
72226160550430461
oct241774467650047
943365805267312
1011132100104231
113602108328477
1212b958597439b
136299a2421cc2
142a6b21917131
15144888aa5d3b
hexa1fe4df5027

11132100104231 has 2 divisors, whose sum is σ = 11132100104232. Its totient is φ = 11132100104230.

The previous prime is 11132100104219. The next prime is 11132100104239. The reversal of 11132100104231 is 13240100123111.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11132100104231 is a prime.

It is a super-2 number, since 2×111321001042312 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11132100104239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566050052115 + 5566050052116.

It is an arithmetic number, because the mean of its divisors is an integer number (5566050052116).

Almost surely, 211132100104231 is an apocalyptic number.

11132100104231 is a deficient number, since it is larger than the sum of its proper divisors (1).

11132100104231 is an equidigital number, since it uses as much as digits as its factorization.

11132100104231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 11132100104231 its reverse (13240100123111), we get a palindrome (24372200227342).

The spelling of 11132100104231 in words is "eleven trillion, one hundred thirty-two billion, one hundred million, one hundred four thousand, two hundred thirty-one".