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11132101537 is a prime number
BaseRepresentation
bin10100101111000011…
…00110001110100001
31001201211000100110221
422113201212032201
5140244304222122
65040343323041
7542602205344
oct122741461641
931654010427
1011132101537
1147a2865717
1221a8150481
1310853ca83b
1477865a45b
154524856c7
hex2978663a1

11132101537 has 2 divisors, whose sum is σ = 11132101538. Its totient is φ = 11132101536.

The previous prime is 11132101531. The next prime is 11132101543. The reversal of 11132101537 is 73510123111.

It is a balanced prime because it is at equal distance from previous prime (11132101531) and next prime (11132101543).

It can be written as a sum of positive squares in only one way, i.e., 10262500416 + 869601121 = 101304^2 + 29489^2 .

It is an emirp because it is prime and its reverse (73510123111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11132101537 is a prime.

It is not a weakly prime, because it can be changed into another prime (11132101531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566050768 + 5566050769.

It is an arithmetic number, because the mean of its divisors is an integer number (5566050769).

Almost surely, 211132101537 is an apocalyptic number.

It is an amenable number.

11132101537 is a deficient number, since it is larger than the sum of its proper divisors (1).

11132101537 is an equidigital number, since it uses as much as digits as its factorization.

11132101537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 630, while the sum is 25.

Adding to 11132101537 its reverse (73510123111), we get a palindrome (84642224648).

The spelling of 11132101537 in words is "eleven billion, one hundred thirty-two million, one hundred one thousand, five hundred thirty-seven".