Base | Representation |
---|---|
bin | 10000001100110000100… |
… | …000010101010110111001 |
3 | 10221102101112121011012001 |
4 | 100030300200111112321 |
5 | 121214323314441441 |
6 | 2211222440221001 |
7 | 143266250346025 |
oct | 20146040252671 |
9 | 3842345534161 |
10 | 1113210312121 |
11 | 39a123222016 |
12 | 15b8b7a6a761 |
13 | 80c8a904bcb |
14 | 3bc45b3b385 |
15 | 1de555e7731 |
hex | 103308155b9 |
1113210312121 has 4 divisors (see below), whose sum is σ = 1113236460112. Its totient is φ = 1113184164132.
The previous prime is 1113210312103. The next prime is 1113210312143. The reversal of 1113210312121 is 1212130123111.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1113210312121 - 211 = 1113210310073 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1113210312101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13010031 + ... + 13095316.
It is an arithmetic number, because the mean of its divisors is an integer number (278309115028).
Almost surely, 21113210312121 is an apocalyptic number.
It is an amenable number.
1113210312121 is a deficient number, since it is larger than the sum of its proper divisors (26147991).
1113210312121 is an equidigital number, since it uses as much as digits as its factorization.
1113210312121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26147990.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 1113210312121 its reverse (1212130123111), we get a palindrome (2325340435232).
The spelling of 1113210312121 in words is "one trillion, one hundred thirteen billion, two hundred ten million, three hundred twelve thousand, one hundred twenty-one".
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