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11132113 is a prime number
BaseRepresentation
bin101010011101…
…110011010001
3202221120101111
4222131303101
510322211423
61034333321
7163423066
oct52356321
922846344
1011132113
1163137a3
12388a241
1323c9c65
14169ac6d
15e9d60d
hexa9dcd1

11132113 has 2 divisors, whose sum is σ = 11132114. Its totient is φ = 11132112.

The previous prime is 11132083. The next prime is 11132123. The reversal of 11132113 is 31123111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10837264 + 294849 = 3292^2 + 543^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11132113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11132093 and 11132102.

It is not a weakly prime, because it can be changed into another prime (11132123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566056 + 5566057.

It is an arithmetic number, because the mean of its divisors is an integer number (5566057).

Almost surely, 211132113 is an apocalyptic number.

It is an amenable number.

11132113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11132113 is an equidigital number, since it uses as much as digits as its factorization.

11132113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 18, while the sum is 13.

The square root of 11132113 is about 3336.4821294291. The cubic root of 11132113 is about 223.2848217694.

Adding to 11132113 its reverse (31123111), we get a palindrome (42255224).

The spelling of 11132113 in words is "eleven million, one hundred thirty-two thousand, one hundred thirteen".