111322122013 has 4 divisors (see below), whose sum is σ = 111323147040. Its totient is φ = 111321096988.

The previous prime is 111322122001. The next prime is 111322122031. The reversal of 111322122013 is 310221223111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 310221223111 = 1811 ⋅171298301.

It is a cyclic number.

It is not a de Polignac number, because 111322122013 - 2²⁵ = 111288567581 is a prime.

It is a super-2 number, since 2×111322122013² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111322128013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 327295 + ... + 574252.

It is an arithmetic number, because the mean of its divisors is an integer number (27830786760).

Almost surely, 2^111322122013 is an apocalyptic number.

It is an amenable number.

111322122013 is a deficient number, since it is larger than the sum of its proper divisors (1025027).

111322122013 is an equidigital number, since it uses as much as digits as its factorization.

111322122013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1025026.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 111322122013 its reverse (310221223111), we get a palindrome (421543345124).

It can be divided in two parts, 11132 and 2122013, that added together give a triangular number (2133145 = T₂₀₆₅).

The spelling of 111322122013 in words is "one hundred eleven billion, three hundred twenty-two million, one hundred twenty-two thousand, thirteen".