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11132223151333 is a prime number
BaseRepresentation
bin1010000111111110110000…
…1101001101110011100101
31110102020012202211201020111
42201333230031031303211
52424342243111320313
635402023412333021
72226163603342414
oct241775415156345
943366182751214
1011132223151333
113602170830599
1212b95bb014171
136299c1a74b3b
142a6b33dc747b
151448947ae43d
hexa1fec34dce5

11132223151333 has 2 divisors, whose sum is σ = 11132223151334. Its totient is φ = 11132223151332.

The previous prime is 11132223151307. The next prime is 11132223151339. The reversal of 11132223151333 is 33315132223111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9146711068609 + 1985512082724 = 3024353^2 + 1409082^2 .

It is a cyclic number.

It is not a de Polignac number, because 11132223151333 - 225 = 11132189596901 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11132223151295 and 11132223151304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11132223151339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566111575666 + 5566111575667.

It is an arithmetic number, because the mean of its divisors is an integer number (5566111575667).

Almost surely, 211132223151333 is an apocalyptic number.

It is an amenable number.

11132223151333 is a deficient number, since it is larger than the sum of its proper divisors (1).

11132223151333 is an equidigital number, since it uses as much as digits as its factorization.

11132223151333 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 9720, while the sum is 31.

Adding to 11132223151333 its reverse (33315132223111), we get a palindrome (44447355374444).

The spelling of 11132223151333 in words is "eleven trillion, one hundred thirty-two billion, two hundred twenty-three million, one hundred fifty-one thousand, three hundred thirty-three".