Base | Representation |
---|---|
bin | 10000001100110001011… |
… | …001001011101111000111 |
3 | 10221102102120122021222112 |
4 | 100030301121023233013 |
5 | 121214341123334134 |
6 | 2211224131451235 |
7 | 143266521125306 |
oct | 20146131135707 |
9 | 3842376567875 |
10 | 1113225214919 |
11 | 39a130680784 |
12 | 15b900a56b1b |
13 | 80c90a2222c |
14 | 3bc47ada43d |
15 | 1de56a8d1ce |
hex | 1033164bbc7 |
1113225214919 has 2 divisors, whose sum is σ = 1113225214920. Its totient is φ = 1113225214918.
The previous prime is 1113225214901. The next prime is 1113225214939. The reversal of 1113225214919 is 9194125223111.
It is a weak prime.
It is an emirp because it is prime and its reverse (9194125223111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1113225214919 - 216 = 1113225149383 is a prime.
It is a super-2 number, since 2×11132252149192 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113225214939) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556612607459 + 556612607460.
It is an arithmetic number, because the mean of its divisors is an integer number (556612607460).
Almost surely, 21113225214919 is an apocalyptic number.
1113225214919 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113225214919 is an equidigital number, since it uses as much as digits as its factorization.
1113225214919 is an evil number, because the sum of its binary digits is even.
The product of its digits is 38880, while the sum is 41.
The spelling of 1113225214919 in words is "one trillion, one hundred thirteen billion, two hundred twenty-five million, two hundred fourteen thousand, nine hundred nineteen".
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