Base | Representation |
---|---|
bin | 10000001100110001110… |
… | …111101001001110101011 |
3 | 10221102110010122222111212 |
4 | 100030301313221032223 |
5 | 121214400144400133 |
6 | 2211225014543335 |
7 | 143266646033456 |
oct | 20146167511653 |
9 | 3842403588455 |
10 | 1113233200043 |
11 | 39a135135058 |
12 | 15b903667b4b |
13 | 80c92589963 |
14 | 3bc48bb849d |
15 | 1de57619148 |
hex | 10331de93ab |
1113233200043 has 2 divisors, whose sum is σ = 1113233200044. Its totient is φ = 1113233200042.
The previous prime is 1113233199989. The next prime is 1113233200061. The reversal of 1113233200043 is 3400023323111.
It is a strong prime.
It is an emirp because it is prime and its reverse (3400023323111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1113233200043 - 212 = 1113233195947 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1113233199991 and 1113233200018.
It is not a weakly prime, because it can be changed into another prime (1113233200073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556616600021 + 556616600022.
It is an arithmetic number, because the mean of its divisors is an integer number (556616600022).
Almost surely, 21113233200043 is an apocalyptic number.
1113233200043 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113233200043 is an equidigital number, since it uses as much as digits as its factorization.
1113233200043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 1113233200043 its reverse (3400023323111), we get a palindrome (4513256523154).
The spelling of 1113233200043 in words is "one trillion, one hundred thirteen billion, two hundred thirty-three million, two hundred thousand, forty-three".
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