Base | Representation |
---|---|
bin | 10100101111000101… |
… | …00100011111010001 |
3 | 1001201211111022022021 |
4 | 22113202210133101 |
5 | 140244340402221 |
6 | 5040353011441 |
7 | 542604320014 |
oct | 122742443721 |
9 | 31654438267 |
10 | 11132356561 |
11 | 47a2a1a287 |
12 | 21a8253b81 |
13 | 1085489941 |
14 | 7786c537b |
15 | 4524d6041 |
hex | 2978a47d1 |
11132356561 has 2 divisors, whose sum is σ = 11132356562. Its totient is φ = 11132356560.
The previous prime is 11132356513. The next prime is 11132356603. The reversal of 11132356561 is 16565323111.
11132356561 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7811024400 + 3321332161 = 88380^2 + 57631^2 .
It is a cyclic number.
It is not a de Polignac number, because 11132356561 - 29 = 11132356049 is a prime.
It is not a weakly prime, because it can be changed into another prime (11132326561) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566178280 + 5566178281.
It is an arithmetic number, because the mean of its divisors is an integer number (5566178281).
Almost surely, 211132356561 is an apocalyptic number.
It is an amenable number.
11132356561 is a deficient number, since it is larger than the sum of its proper divisors (1).
11132356561 is an equidigital number, since it uses as much as digits as its factorization.
11132356561 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 16200, while the sum is 34.
Adding to 11132356561 its reverse (16565323111), we get a palindrome (27697679672).
The spelling of 11132356561 in words is "eleven billion, one hundred thirty-two million, three hundred fifty-six thousand, five hundred sixty-one".
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