11132421243133 has 2 divisors, whose sum is σ = 11132421243134. Its totient is φ = 11132421243132.

The previous prime is 11132421243101. The next prime is 11132421243179. The reversal of 11132421243133 is 33134212423111.

11132421243133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10859647978404 + 272773264729 = 3295398^2 + 522277^2 .

It is an emirp because it is prime and its reverse (33134212423111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11132421243133 - 2⁵ = 11132421243101 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11132421243095 and 11132421243104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11132421253133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566210621566 + 5566210621567.

It is an arithmetic number, because the mean of its divisors is an integer number (5566210621567).

Almost surely, 2^{11132421243133} is an apocalyptic number.

It is an amenable number.

11132421243133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11132421243133 is an equidigital number, since it uses as much as digits as its factorization.

11132421243133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10368, while the sum is 31.

Adding to 11132421243133 its reverse (33134212423111), we get a palindrome (44266633666244).

The spelling of 11132421243133 in words is "eleven trillion, one hundred thirty-two billion, four hundred twenty-one million, two hundred forty-three thousand, one hundred thirty-three".