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11132433301 = 112471957523
BaseRepresentation
bin10100101111000101…
…10111001110010101
31001201211122012120111
422113202313032111
5140244400331201
65040354403021
7542605056523
oct122742671625
931654565514
1011132433301
1147a2a71a00
1221a8290471
1310854b5852
14778705313
154524edb51
hex2978b7395

11132433301 has 12 divisors (see below), whose sum is σ = 12496833216. Its totient is φ = 9905061320.

The previous prime is 11132433293. The next prime is 11132433311. The reversal of 11132433301 is 10333423111.

It is not a de Polignac number, because 11132433301 - 23 = 11132433293 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11132433311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 973075 + ... + 984448.

It is an arithmetic number, because the mean of its divisors is an integer number (1041402768).

Almost surely, 211132433301 is an apocalyptic number.

11132433301 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

11132433301 is a deficient number, since it is larger than the sum of its proper divisors (1364399915).

11132433301 is a wasteful number, since it uses less digits than its factorization.

11132433301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1957592 (or 1957581 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 11132433301 its reverse (10333423111), we get a palindrome (21465856412).

The spelling of 11132433301 in words is "eleven billion, one hundred thirty-two million, four hundred thirty-three thousand, three hundred one".

Divisors: 1 11 47 121 517 5687 1957523 21532753 92003581 236860283 1012039391 11132433301