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11133000113 = 61318161501
BaseRepresentation
bin10100101111001010…
…00001100110110001
31001201212201000002112
422113211001212301
5140300022000423
65040414455105
7542612640164
oct122745014661
931655630075
1011133000113
1147a3319844
1221a8504495
131085653841
14778811adb
154525b1a78
hex2979419b1

11133000113 has 4 divisors (see below), whose sum is σ = 11151162228. Its totient is φ = 11114838000.

The previous prime is 11133000101. The next prime is 11133000119. The reversal of 11133000113 is 31100033111.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3189199729 + 7943800384 = 56473^2 + 89128^2 .

It is a cyclic number.

It is not a de Polignac number, because 11133000113 - 210 = 11132999089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11133000119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9080138 + ... + 9081363.

It is an arithmetic number, because the mean of its divisors is an integer number (2787790557).

Almost surely, 211133000113 is an apocalyptic number.

It is an amenable number.

11133000113 is a deficient number, since it is larger than the sum of its proper divisors (18162115).

11133000113 is an equidigital number, since it uses as much as digits as its factorization.

11133000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18162114.

The product of its (nonzero) digits is 27, while the sum is 14.

Adding to 11133000113 its reverse (31100033111), we get a palindrome (42233033224).

The spelling of 11133000113 in words is "eleven billion, one hundred thirty-three million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 613 18161501 11133000113