Base | Representation |
---|---|
bin | 11001010100000100001001… |
… | …110100011100100101100111 |
3 | 112121012001012221210222100221 |
4 | 121110010021310130211213 |
5 | 104043012331034220033 |
6 | 1032440145041145211 |
7 | 32310220324264054 |
oct | 3124041164344547 |
9 | 477161187728327 |
10 | 111330012023143 |
11 | 3252287a4685a1 |
12 | 105a060392b207 |
13 | 4a174b50b0374 |
14 | 1d6c58938402b |
15 | cd0e3833912d |
hex | 654109d1c967 |
111330012023143 has 2 divisors, whose sum is σ = 111330012023144. Its totient is φ = 111330012023142.
The previous prime is 111330012023129. The next prime is 111330012023177. The reversal of 111330012023143 is 341320210033111.
It is a weak prime.
It is an emirp because it is prime and its reverse (341320210033111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 111330012023143 - 29 = 111330012022631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111330012023443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55665006011571 + 55665006011572.
It is an arithmetic number, because the mean of its divisors is an integer number (55665006011572).
Almost surely, 2111330012023143 is an apocalyptic number.
111330012023143 is a deficient number, since it is larger than the sum of its proper divisors (1).
111330012023143 is an equidigital number, since it uses as much as digits as its factorization.
111330012023143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 111330012023143 its reverse (341320210033111), we get a palindrome (452650222056254).
The spelling of 111330012023143 in words is "one hundred eleven trillion, three hundred thirty billion, twelve million, twenty-three thousand, one hundred forty-three".
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