Base | Representation |
---|---|
bin | 10100101111001010… |
… | …00100000001100111 |
3 | 1001201212201111200120 |
4 | 22113211010001213 |
5 | 140300022310043 |
6 | 5040415013023 |
7 | 542613011112 |
oct | 122745040147 |
9 | 31655644616 |
10 | 11133010023 |
11 | 47a3326233 |
12 | 21a850a173 |
13 | 10856581c5 |
14 | 778815579 |
15 | 4525b4983 |
hex | 297944067 |
11133010023 has 4 divisors (see below), whose sum is σ = 14844013368. Its totient is φ = 7422006680.
The previous prime is 11133009961. The next prime is 11133010027. The reversal of 11133010023 is 32001033111.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32001033111 = 3 ⋅10667011037.
It is a cyclic number.
It is not a de Polignac number, because 11133010023 - 212 = 11133005927 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11133009984 and 11133010011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11133010027) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1855501668 + ... + 1855501673.
It is an arithmetic number, because the mean of its divisors is an integer number (3711003342).
Almost surely, 211133010023 is an apocalyptic number.
11133010023 is a deficient number, since it is larger than the sum of its proper divisors (3711003345).
11133010023 is an equidigital number, since it uses as much as digits as its factorization.
11133010023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3711003344.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 11133010023 its reverse (32001033111), we get a palindrome (43134043134).
The spelling of 11133010023 in words is "eleven billion, one hundred thirty-three million, ten thousand, twenty-three".
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