11133012113 has 4 divisors (see below), whose sum is σ = 11492141568. Its totient is φ = 10773882660.

The previous prime is 11133012109. The next prime is 11133012119. The reversal of 11133012113 is 31121033111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11133012113 - 2² = 11133012109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11133012091 and 11133012100.

It is not an unprimeable number, because it can be changed into a prime (11133012119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 179564681 + ... + 179564742.

It is an arithmetic number, because the mean of its divisors is an integer number (2873035392).

Almost surely, 2^11133012113 is an apocalyptic number.

It is an amenable number.

11133012113 is a deficient number, since it is larger than the sum of its proper divisors (359129455).

11133012113 is an equidigital number, since it uses as much as digits as its factorization.

11133012113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 359129454.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11133012113 its reverse (31121033111), we get a palindrome (42254045224).

The spelling of 11133012113 in words is "eleven billion, one hundred thirty-three million, twelve thousand, one hundred thirteen".