Base | Representation |
---|---|
bin | 10000001100110101111… |
… | …011001010111010110011 |
3 | 10221102121212200102122021 |
4 | 100030311323022322303 |
5 | 121220020103431311 |
6 | 2211235445052311 |
7 | 143301433226320 |
oct | 20146573127263 |
9 | 3842555612567 |
10 | 1113301233331 |
11 | 39a16a582511 |
12 | 15b9223b7097 |
13 | 80ca36ba241 |
14 | 3bc53c47b47 |
15 | 1de5d5a7171 |
hex | 10335ecaeb3 |
1113301233331 has 32 divisors (see below), whose sum is σ = 1371608017920. Its totient is φ = 881946240000.
The previous prime is 1113301233313. The next prime is 1113301233353. The reversal of 1113301233331 is 1333321033111.
It is not a de Polignac number, because 1113301233331 - 25 = 1113301233299 is a prime.
It is a super-2 number, since 2×11133012333312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1113301233296 and 1113301233305.
It is not an unprimeable number, because it can be changed into a prime (1113301233431) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1858215 + ... + 2383183.
It is an arithmetic number, because the mean of its divisors is an integer number (42862750560).
Almost surely, 21113301233331 is an apocalyptic number.
1113301233331 is a deficient number, since it is larger than the sum of its proper divisors (258306784589).
1113301233331 is a wasteful number, since it uses less digits than its factorization.
1113301233331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 525315.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 1113301233331 its reverse (1333321033111), we get a palindrome (2446622266442).
The spelling of 1113301233331 in words is "one trillion, one hundred thirteen billion, three hundred one million, two hundred thirty-three thousand, three hundred thirty-one".
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