Base | Representation |
---|---|
bin | 10000001100110110011… |
… | …101000101000001110111 |
3 | 10221102122111102000202001 |
4 | 100030312131011001313 |
5 | 121220024342401403 |
6 | 2211240403400131 |
7 | 143301601620154 |
oct | 20146635050167 |
9 | 3842574360661 |
10 | 1113310122103 |
11 | 39a1745a3803 |
12 | 15b925383047 |
13 | 80ca54b007a |
14 | 3bc550bd22b |
15 | 1de5e260c1d |
hex | 10336745077 |
1113310122103 has 2 divisors, whose sum is σ = 1113310122104. Its totient is φ = 1113310122102.
The previous prime is 1113310122049. The next prime is 1113310122107. The reversal of 1113310122103 is 3012210133111.
It is a strong prime.
It is an emirp because it is prime and its reverse (3012210133111) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1113310122103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113310122107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556655061051 + 556655061052.
It is an arithmetic number, because the mean of its divisors is an integer number (556655061052).
Almost surely, 21113310122103 is an apocalyptic number.
1113310122103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113310122103 is an equidigital number, since it uses as much as digits as its factorization.
1113310122103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 1113310122103 its reverse (3012210133111), we get a palindrome (4125520255214).
The spelling of 1113310122103 in words is "one trillion, one hundred thirteen billion, three hundred ten million, one hundred twenty-two thousand, one hundred three".
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