11133110013407 has 2 divisors, whose sum is σ = 11133110013408. Its totient is φ = 11133110013406.

The previous prime is 11133110013301. The next prime is 11133110013427. The reversal of 11133110013407 is 70431001133111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11133110013407 - 2¹⁸ = 11133109751263 is a prime.

It is a super-3 number, since 3×11133110013407³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11133110013427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566555006703 + 5566555006704.

It is an arithmetic number, because the mean of its divisors is an integer number (5566555006704).

Almost surely, 2^{11133110013407} is an apocalyptic number.

11133110013407 is a deficient number, since it is larger than the sum of its proper divisors (1).

11133110013407 is an equidigital number, since it uses as much as digits as its factorization.

11133110013407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 756, while the sum is 26.

Adding to 11133110013407 its reverse (70431001133111), we get a palindrome (81564111146518).

The spelling of 11133110013407 in words is "eleven trillion, one hundred thirty-three billion, one hundred ten million, thirteen thousand, four hundred seven".