11133120113 has 2 divisors, whose sum is σ = 11133120114. Its totient is φ = 11133120112.

The previous prime is 11133120049. The next prime is 11133120137. The reversal of 11133120113 is 31102133111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8291377249 + 2841742864 = 91057^2 + 53308^2 .

It is a cyclic number.

It is not a de Polignac number, because 11133120113 - 2⁶ = 11133120049 is a prime.

It is a super-3 number, since 3×11133120113³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11133120091 and 11133120100.

It is not a weakly prime, because it can be changed into another prime (11133122113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566560056 + 5566560057.

It is an arithmetic number, because the mean of its divisors is an integer number (5566560057).

Almost surely, 2^11133120113 is an apocalyptic number.

It is an amenable number.

11133120113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11133120113 is an equidigital number, since it uses as much as digits as its factorization.

11133120113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11133120113 its reverse (31102133111), we get a palindrome (42235253224).

The spelling of 11133120113 in words is "eleven billion, one hundred thirty-three million, one hundred twenty thousand, one hundred thirteen".